15(a+2)^2-4(a+2)-3=0

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Solution for 15(a+2)^2-4(a+2)-3=0 equation: 



15(a+2)^2-4(a+2)-3=0

We multiply parentheses

15(a+2)^2-4a-8-3=0

We add all the numbers together, and all the variables

-4a+15(a+2)^2-11=0

We move all terms containing a to the left, all other terms to the right

-4a+15(a+2)^2=11

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